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Marta_Voda [28]
3 years ago
5

What is 5m2- 15m- 200

Mathematics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

5(m + 5) (m - 8)

Step-by-step explanation:

5m2- 15m- 200

Start by pulling 5 out.

5(m^2 - 3m - 40)

We consider all factors of 40  

1    40

2   20

4    10

5     8

Based on the middle term we know that 5   and 8 are our best option.

5(m     5) (m     8)

We know the signs have to be one + and one -  because a - * - = + and + * + = +

Since 5 - 8 would give us -3 we know that our answer is

5(m + 5) (m - 8)

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Jillian ran 40 miles in one week. Her friend Lacy ran 5/8 the distance that Jillian ran . How many miles did Lacy run ?
Korvikt [17]
Lacy ran 25 miles.

40/8=5  5*5=25
5 0
2 years ago
The volume of a rectangular prism is 2x^3 - 6x^2 + 8x , and the volume of a cube is 27x^3. What is the total volume of the prism
AleksAgata [21]

Answer:

\displaystyle V_{P + C} = 29x^3 - 6x^2 + 8x

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

<em />\displaystyle V_P = 2x^3 - 6x^2 + 8x<em />

<em />\displaystyle V_C = 27x^3<em />

<em />

<u>Step 2: Find Combined Volume</u>

  1. [Set up] Add:                                                                                                     \displaystyle V_P + V_C = V_{P + C}
  2. Substitute in variables:                                                                                    \displaystyle V_{P + C} = 27x^3 + 2x^3 - 6x^2 + 8x
  3. Combine like terms:                                                                                        \displaystyle V_{P + C} = 29x^3 - 6x^2 + 8x
8 0
2 years ago
I need help on this question. Does anybody know how to do it??
marta [7]
1/3 x 14
2/3 x 7
4/6 x 7
2/6 x 14
1/3 x 28/2
1/3 x 42/3
4 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
there are four Defenders on a soccer team that this represents 20% of the players on the team which equation can be used to find
gladu [14]
4=(total players on the team) x 0.2
(total players on the team) = 4/0.2
(total players on the team) = 20
****
20% is the same as 0.2.
2 is 20% of 10.
to find 10, divide 2 by 0.2
2/0.2=10
4 is 20% of something
to find 'something', divide 4 by 0.2
4/0.2=20
7 0
3 years ago
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