AC=3x+3, AB=-1/2x and BC=11

Given that f(x)= 3x^2-5x +3 and g(x)= -x^2 + 17 find (f-g) (x)

Sliva [168]

4x^2-5x-14 is your answer :)

3 0

3 years ago

Determine whether the following study is an observational study or an experiment. If the study is an experiment, identify the co

horrorfan [7]

Answer:

A. whether a woman took hormones.

B. whether to woman in the study had a heart attack.

D. access to health care

Step-by-step explanation:

The study conducted to observe the menopausal woman must be supported with their health history. Some woman may have menopause at an early age while other go towards this at a later age. This can be due to smoking, hormone intake, severe diseases like heart attack or cancer and their routine health checkup details. There variables must be observed and included in experiment to reach a conclusion.

6 0

3 years ago

The sum of 14 and 3 divided by r

labwork [276]

Answer:

?

Step-by-step explanation:

7 0

3 years ago

Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month. During the 12 month period, how many time

Nana76 [90]

Answer:

Jenny save 4 times $\$ 250$ for the month

Step-by-step explanation:

Given Jenny has saved $\$3,800$ over the last 12 months.

She saved either $\$250$ or $\$350$ a month.

Let the number of months to save $\$250$ be x

Let the number of months to save $\$350$ be y

Total period is 12 month.

$x+y=12 \ \ \ \ equation\ 1$

Jenny has saved $3,800 over the last 12 months.

$250x+350y=3800$

Dividing both side from 50 we get,

$\frac{250}{50}x+\frac{350}{50}y= \frac{3800}{50}$

$5x+7y=76 \ \ \ \ equation\ 2$

Now Multiplying equation 1 by 5 we get,

$5\times(x+y)=5\times 12\\5x+5y=60\ \ \ \ equation \ 3$

Now Subtracting Equation 3 by equation 2 we get,

$(5x+7y=76)-(5x+5y=60)\\2y=16\\y=\frac{16}{2}= 8$

Substituting the value of y in equation 1 we get,

$x+y=12\\x+8=12\\x=12-8\\x=4$

∴ Jenny save 4 Months of $\$ 250$ and 8 Months of $\$ 350$ in a 12 month duration

4 0

3 years ago

Read 2 more answers

A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately

Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

$z=\frac{\bar x-\mu}{\sigma/\sqrt N}$

where

$\bar x=mean\; of\;the \;sample$

$\mu=mean\; established\; in\; H_0$

$\sigma=standard \; deviation$

N = size of the sample.

So,

$z=\frac{185-175}{20/\sqrt {10}}=1.5811$

$\boxed {z=1.5811}$

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of 1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of 1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is

$\boxed {p=0.057}$

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

Step 1

Compute $\bar x_{critical}$