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3 years ago

Here's the question sorry

Mathematics

1 answer:

Lunna [17]3 years ago

6 0

L = total number of slices for Luke

K = total number of slices for Kira

A = total number of slices for Ali

$\stackrel{\textit{two thirds of all slices}}{\cfrac{2}{3}L}=4\implies 2L=12\implies L=\cfrac{12}{2}\implies L=6 \\\\\\ \stackrel{\textit{two thirds of all slices}}{\cfrac{2}{3}K}=6\implies 2K=18\implies K=\cfrac{18}{2}\implies K=9 \\\\\\ \stackrel{\textit{two thirds of all slices}}{\cfrac{2}{3}A}=8\implies 2A=24\implies A=\cfrac{24}{2}\implies A=12$

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Rewrite the equation in standard form y= 4/5x+0.85. Enter answer as ax+by=c or ax+by+c=0

Paraphin [41]

At very minimum, move (4/5)x to the other side of the given equation. Then:

-(4/5)x + y = 0.85. This is the equation in standard form.

3 0

3 years ago

Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of ? (5 points

Irina18 [472]

Answer:

It will be 3 in by 4 in

Step-by-step explanation:

Original dimension is 6 in by 8 in

If he scale it down by a factor of 1/2

The new dimension will be

1/2(6) by 1/2(8)

= 3 by 4

= 3 in by 4 in

7 0

3 years ago

A tree makes a shadow that is 14 ft long. Rachel is 6 ft tall. when she id standing near the tree, her shadow is 3.5 ft long. wh

ankoles [38]

The triangle that is formed from by connecting the shadow, the tree and the endpoints of each is a right triangle. The two triangles formed (by the tree and its shadow, and by Rachel and her shadow) are similar. In similar triangles, the corresponding sides are proportional. Thus, to give the numerical answer to this item,
length of the tree/14 ft = 6 ft / 3.5 ft
length of the tree = 24 ft

5 0

3 years ago

What function has the same y intercept as the function y=2/x -3

Tema [17]

$The \: answer \: is \: none, \: because \: the \: function \: y = \frac{2}{x} - 3 \: doesn't \: have \: a \: y \: intercept.$

3 0

3 years ago

Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)

Xelga [282]

Answer:

$\frac{x^2}{16}-\frac{b^2}{4}=1$

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4$

The foci c is at +/-2√5, using c² = a² + b²:

$c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2$

Substituting the value of a and b to get the equation of the hyperbola:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1$

5 0

3 years ago

Here's the question sorry​

Here's the question sorry