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marshall27 [118]
3 years ago
11

Determine the intervals on which the function is increasing, decreasing, and constant. An absolute value function is shown facin

g down with a vertex of -1,0.

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

Increasing on: x\:

Decreasing on: x\:>\:-1

Constant at : x=-1

Step-by-step explanation:

The given absolute value function is f(x)=|x+1|.

A function is said to be increasing if for all x_1\:>\:x_0,  f(x_1)\:>\:f(x_0)

From the graph, we can observe that the graph has a positive slope for all x-values less than -1. This implies that the interval of increase is x\: or (-\infty,-1)

We can also observe that, the slope of this function is negative on the interval:x\:>\:-1 or (-1,\infty).

At x=-1, the function is neither increasing nor decreasing. We say the function is constant at x=-1

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tatiyna
Look this up in Photomath
6 0
3 years ago
How many times smaller is the value of the 6 in 621 than the value of the 6 in 6420
SashulF [63]
The 6 in 621 is in the hundred's place, so alone it would equal 600.

However, the 6 in 6,420 is in the thousand's place, so it alone would equal 6,000. 
 
The question is asking how many times smaller is the value of 6 in these two numbers. Therefore, you need to divide 6,000 by 600.

Your answer should be 10.





5 0
4 years ago
Which of the following does not factor as a perfect square trinomial?
Ede4ka [16]

Answer:

Option C. x^2-18x-81

Step-by-step explanation:

A. 16a^2-72a+81

x^2-2xy+y^2=(x-y)^2

x^2=16a^2→sqrt(x^2)=sqrt(16a^2)→x=sqrt(16) sqrt(a^2)→x=4a

y^2=81→sqrt(y^2)=sqrt(81)→y=9

2xy=2(4a)(9)→2xy=72a equal to the second term of the expression, then we can factor as a perfect square trinomial:

16a^2-72a+81=(4a-9)^2


B. 169x^2+26xy+y^2

a^2+2ab+b^2=(a+b)^2

a^2=169x^2→sqrt(a^2)=sqrt(169x^2)→a=sqrt(169) sqrt(x^2)→a=13x

b^2=y^2→sqrt(b^2)=sqrt(y^2)→b=y

2ab=2(13x)(y)→2ab=26xy equal to the second term of the expression, then we can factor as a perfect square trinomial:

169x^2+26xy+y^2=(13x+y)^2


C. x^2-18x-81

a^2+2ab+b^2=(a+b)^2

This expression does not factor as a perfect square trinomial because the third term is negative (-81).


D. 4x^2+4x+1

a^2+2ab+b^2=(a+b)^2

a^2=4x^2→sqrt(a^2)=sqrt(4x^2)→a=sqrt(4) sqrt(x^2)→a=2x

b^2=1→sqrt(b^2)=sqrt(1)→b=1

2ab=2(2x)(1)→2ab=4x equal to the second term of the expression, then we can factor as a perfect square trinomial:

4x^2+4x+1=(2x+1)^2

4 0
3 years ago
Please help!! 11 points!!
MariettaO [177]

Answer:3x < 8x - 3

Step-by-step explanation:

5 0
3 years ago
HELPPP I DONT KNOW WHAT TO DO
Veronika [31]

a/c

Step-by-step explanation:

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3 years ago
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