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Vladimir79 [104]
2 years ago
9

WILL MARK BRAINLIEST!!!!! PLEASE ANSWER AND EXPLAIN!!! thank you

Mathematics
1 answer:
mafiozo [28]2 years ago
7 0
Answer is B. because angle akl is congruent to zwx
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WILL GIVE BRAINLYEST
Westkost [7]

Answer: Answer is D, a 55° angle

Step-by-step explanation:

5 0
2 years ago
A pool pass costs $30 for the first month and $15 each additional month. Construct an explicit rule in function notation to mode
noname [10]

Answer:

F(n)=15(n+1)    [ where n is number of months]

F(12)=195

Step-by-step explanation:

Pool pass cost for first month =$30

Pool pass cost after first month = $15 for each month

The total amount charged by the pool can be expressed as a  function F(n) where n represents the number of months.

F(n)=15(n-1)+30

This can be simplified by using distribution.

F(n)=(15n-15)+30

F(n)=15n-15+30

F(n)=15n+15

Take 15 as greatest common factor.

∴ F(n)=15(n+1)

For n=12

F(12)=15(12+1)

F(12)=15(13)

F(12)=195

∴ Amount charged by pool for 12 months = $195

4 0
3 years ago
Please Help! Solve the equation for x.
SOVA2 [1]

Answer:

A

Step-by-step explanation:

Given

\frac{1}{3} x - 8 = - 12 ( multiply through by 3 to clear the fraction )

x - 24 = - 36 ( add 24 to both sides )

x = - 12 → A

6 0
3 years ago
there are 100 movies at the store 30/100 are action movies 50/100 are comedies and 20/100 are adventure movies what part of the
pogonyaev

Answer:30 action and 50 comedies which is 80/100 or 80%/100%

Step-by-step explanation:

8 0
3 years ago
You have a wooden rod which is 24 1/2 inches long. Carlos needs a piece which is 8 3/4 inches long and Amanda needs a piece whic
ipn [44]

Answer:

8 3/4 inches

Step-by-step explanation:

Total length of the rod = 24 1/2 inches

Carlos = 8 3/4 inches

Amanda = 6 3/8 inches

length of the rod remaining = Total length - ( Carlos + Amanda)

= 24 1/2 - (8 3/4 + 6 3/8)

= 49/2 - (35/4 + 51/8)

= 49/2 - ( 75+51/8)

= 49/2 - 126/8

= 196-126/8

= 70/8

= 8 6/8 inches

= 8 3/4 inches

Length of rod remaining = 8 3/4 inches

6 0
3 years ago
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