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My name is Ann [436]
3 years ago
10

a steady current of 1 AIs flowing through a conducter calculate the number of electrons that flows through conductor in 1second​

Physics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

1 A = 1 C/s. Charge on 1 electron e = 1.6 × 10^(-19) C. No of electrons needed for 1 C of charge = No of electrons that flow in 1 s = (1/1.6 × 10^(-19)) = 6.25 × 10^18.

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an astronaut weighs 8.00x10^2 on the surface of earth. what is the weight of the astronaut 6.37x10^6 meters above the surface of
Marta_Voda [28]
To solve this problem, we use the Law of Universal Gravitation:

F = Gm1m2/d^2

where m1 and m2 are two objects. In this case, earth and man. d is the distance between the objects. Lastly, G is the gravitational constant. Since the mass of the earth and man are constant, this is lumped up with G into k. The equation would be:

F = k/d^2
k = Fd^2
F_{1} d_{1} ^{2} =F_{2} d_{2} ^{2}

The radius of earth, d1, is equal to 6.371E+6 m. Thus, d2 = 2d1

(8E+2)(d1)^2 = F2(2d1)^2

(8E+2)(d1)^2 = 4F2(d1)^2

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F2 = 200 Newtons
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3 years ago
Which statement about magnetic poles is accurate?
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A dog is chasing a squirrel. He runs 5 meters to the left and then 3 meters to the right. What is the distance?
Paraphin [41]

the answer will be 8 meters

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3 years ago
Which of the following pairs of objects could NOT have a magnetic force acting between them?
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4 0
3 years ago
g The ball has a mass of 150 grams. If the ball has a positive charge, what initial velocity must it have at the 200-V level for
Aleonysh [2.5K]

Answer:

u_o = 12.91 m/s

Explanation:

Given:

- mass of the ball m = 0.15 kg

- Spacing between each equipotential line s = 1.0 m

- Charge on the ball is q = 10 mC

Find:

- What initial velocity must it have at the 200-V level for it to reach its maximum height at the 700-V level

Solution:

- Notice that the Electric field lines are directed from Higher potential to lower potential i.e V = + 700 level to V = 200 level. The gravitational acceleration also acts downwards.

- We will compute a resultant acceleration due to gravity and Electric Field as follows:

                                   g' = g + F_e / m

- Where F_e is the Electrostatic Force given by:

                                   F_e = E*q

- Electric field strength is given by:

                                   E = V / d

- Hence,

                                   g' = g + (dV*q/ d*m)

- Input values:

                                  g' = 10 + (500*10^-2 / 5*0.15)

                                  g' = 16.6667 m/s^2

- Now use one of the equation of motions in y-direction:

                                  h_max = u_o ^2 / 2*g'

- Input values where h_max = 5 m

                                 5*2*g' = u_o ^2

                                 u_o = sqrt (166.667)

                                 u_o = 12.91 m/s

4 0
3 years ago
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