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Oxana [17]
3 years ago
12

The Momentum of a man riding his bicycle downhill can be calculated. The bicycle and the man have a combined mass of 40 Kg. The

velocity of the bicycle is 10 m/s. Calculate the momentum.
Physics
1 answer:
shutvik [7]3 years ago
3 0

Answer :The Momentum of a man riding his bicycle downhill is 400 kg m/s.

Explanation:

Mass of the man of bicycle = 40 kg

Velocity of the bicycle = 10 m/s

Momentum = Mass ×  Velocity = 40 kg × 10 m/s = 400 kg m/s

The Momentum of a man riding his bicycle downhill is 400 kg m/s.

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The answer please it’s very simple this is 7th grade science
allochka39001 [22]

The greatest point for kinetic is at the bottom and in the middle it is in half and at the top it is at the highest in potential energy.

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3 years ago
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. An iron cube (ρ = 7860 kg/m3) having sides of 1 cm is submerged in open fresh water (ρ = 1000kg/m3) with its top surface at a
Korolek [52]

Answer:

\Delta P = 98.07\,Pa

Explanation:

The difference between top and bottom surfaces is computed by the following hydrostatic equivalence:

\Delta P = \rho_{w}\cdot g \cdot \Delta h

\Delta P = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.01\,m)

\Delta P = 98.07\,Pa

5 0
3 years ago
The small metal cylinder has a mass of 0.20 kgkg, the coefficient of static friction between the cylinder and the turntable is 0
deff fn [24]

Answer:

velocity of the metal cylinder = 0.343 m/s

Explanation:

Force putting the metal cylinder is given by

F = mv²/r

But this force will balance the frictional force between the metal cylinder and the turntable

The frictional force is given by

μN = μ × mg = 0.08 × 0.2 × 9.81 = 0.15696 N

r = 0.15 m, m = 0.2 kg,

F = mv²/r = 0.2 v²/(0.15) = 1.3333 v²

1.3333 v² = 0.15696

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v = 0.343 m/s

8 0
3 years ago
3) If an object has a net negative charge of 4.0 Coulombs, the object possesses
Pani-rosa [81]
The answer to this question is option 2
3 0
3 years ago
A car initially at rest accelerates at 10m/s^2. The car’s speed after it has traveled 25 meters is most nearly... A.) 0.0m/s B.)
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The car traverses a distance x after time t according to

x=\dfrac12at^2

where a is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is

25\,\mathrm m=\left(5\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=\sqrt 5\,\mathrm s

5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity v after 2 s of travel is given by

v=\left(10\dfrac{\rm m}{\mathrm s^2}\right)(2\,\mathrm s)\approx20\dfrac{\rm m}{\rm s}

which makes C the most likely answer.

3 0
4 years ago
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