1- <span>D. 9x2yz
2- </span><span>C. 2x2y + x2 − 3x + 4
3- </span><span>A. x + 2xyz
4- </span><span>B. 3x + y + z</span>
Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
