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finlep [7]
3 years ago
15

Angela shared a cab with her friends. When they arrived at their destination, they evenly divided the $j fare

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

Total  friends = 3

fare = $ J

She also paid $5 tip

So there is J amount of money splitted into 3 friends.

That means you divide J/3 .

After Angela also  pays additional tip of $5.

That means you also add 5.

So the expression for how much Angela pay in total is: J/3 + 5

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The function y = 8.5(1.1)x models the population in thousands of a town where x is the number of years after 2000. What will be
nikdorinn [45]

Answer:

The population will be at 65.45 in 2007.

Step-by-step explanation:

I graphed the equation below to find the answer.

If this answer is correct, please make me Brainliest!

6 0
3 years ago
Solve for x please show work... i will give you brainliest
Ksenya-84 [330]

Answer:

82°

Step-by-step explanation:

total wine of quadrilateral=360°

130+ 46+ 102 +x =360

x=360- 278

x=82°

5 0
3 years ago
Angle x measures 42°. Find the measure of angle y.
Aneli [31]
The answer is Angle Y equals 138.

angle y= 180 -42 which gives u 138
6 0
3 years ago
At an opening of a new art gallery the owner hired a caterer to serve light snacks. The owner created a budget for 150 people to
Vsevolod [243]

Answer: $357 is more amount budgeted for food increase.

Explanation:

Since we have given that

Number of people according to the budget = 150

Cost of food per person= $4.25

Total cost of food is given by

150\times 4.25=\$637.5

If the number of guests attending the opening was 56% more than expected,

So, number of guests now is given by

150\times 0.56=84\\\\150+84=234

Total cost of food is given by

234\times 4.25=\$994.5

Difference between them is given by

994.5-637.5=\$357

Hence, $357 is more amount budgeted for food increase.

8 0
3 years ago
Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

6 0
3 years ago
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