Answer:
4 feets = 48 inches
2 miles = 10,560 feets
1 2/3 yards = 5 feets
3 1/2 yards = 126 inches
Step-by-step explanation:
Recall :
1 Feet = 12 inches
1 MILE = 5280 feets
1 yard = 36 inches
1 yard = 3 feets
If 1 feet = 12 inches
4 feets will be ; (12 * 4) inches = 48 inches
If 1 mile = 5280 feets
2 miles will be ; (5280 * 2) = 10,560 feets
If 1 yard = 3 feets
1 2/3 yards will be ; (5 /3) * 3 = 5 feets
If 1 yard = 36 inches
3 1/2 yards will be ; (7 /2 ) * 36 = 126 inches
Given that Angelo spends the same amount everyday from the amount in
the lunch card, the function of the amount remaining is a linear function.
- The constant rate of change of the function is; <u>-5.25</u>
- The two ordered pair used to find the constant rate of change are; <u>(1, 44.75) and (2, 39.5)</u>
Reasons:
The amount Angelo's mother put on the lunch card = $50
A possible table of values to the question is presented as follows;
![\begin{tabular}{r|c|c|c|c|}Days&0&1&2&3\\Money Remaining&&44.75&39.5&\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%7Br%7Cc%7Cc%7Cc%7Cc%7C%7DDays%260%261%262%263%5C%5CMoney%20Remaining%26%2644.75%2639.5%26%5Cend%7Barray%7D%5Cright%5D)
Required:
The constant rate of the function that gives the amount remaining from the
amount Angelo's mother put on his lunch card.
Solution:
The two ordered pair that can be used to find the slope or constant rate of change are;
(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)
With the above two ordered pairs, we have the constant rate of change of the function given as follows;

The constant rate of change for the function that gives the amount remaining in the lunch card is; <u>-5.25</u>
Learn more about the constant rate of change of a function here:
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Answer:
(i) ∠ABH = 14.5°
(ii) The length of AH = 4.6 m
Step-by-step explanation:
To solve the problem, we will follow the steps below;
(i)Finding ∠ABH
first lets find <HBC
<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)
46° + <HBC + 90 = 180°
<HBC+ 136° = 180°
subtract 136 from both-side of the equation
<HBC+ 136° - 136° = 180° -136°
<HBC = 44°
lets find <ABC
To do that, we need to first find <BAC
Using the sine rule
= 
A = ?
a=6.9
C=90
c=13.2
= 
sin A = 6.9 sin 90 /13.2
sinA = 0.522727
A = sin⁻¹ ( 0.522727)
A ≈ 31.5 °
<BAC = 31.5°
<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)
31.5° +<ABC + 90° = 180°
<ABC + 121.5° = 180°
subtract 121.5° from both-side of the equation
<ABC + 121.5° - 121.5° = 180° - 121.5°
<ABC = 58.5°
<ABH = <ABC - <HBC
=58.5° - 44°
=14.5°
∠ABH = 14.5°
(ii) Finding the length of AH
To find length AH, we need to first find ∠AHB
<AHB + <BHC = 180° ( angle on a straight line)
<AHB + 46° = 180°
subtract 46° from both-side of the equation
<AHB + 46°- 46° = 180° - 46°
<AHB = 134°
Using sine rule,
= 
AH = 13.2 sin 14.5 / sin 134
AH≈4.6 m
length AH = 4.6 m
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