X²+6x+8= por favor es para mañana
2 answers:
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Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=
=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Answer option A
From the given graph is a Vertical ellipse
Center of ellipse = (-2,-3)
Vertices are (-2,3) and (-2,-9)
Co vertices are (-6,-3) and (2,-3)
The distance between center and vertices = 6, so a= 6
The distance between center and covertices = 4 , so b= 4
The general equation of vertical ellipse is
(h,k) is the center
we know center is (-2,-3)
h= -2, k = -3 , a= 6 and b = 4
The standard equation becomes
Foci are (h,k+c) and (h,k-c)
Plug in the a=6 and b=4
, we know h=-2 and k=-3
Foci are and
Option A is correct