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3 years ago

8

Multiple step problem I know, its a lot.. I will mark brainliest!

1 answer:

natita [175]3 years ago

4 0

A)During 0 week old factory have 40 more products than the new factory.
B)I am so sorry that I forgot how to find the. Rate of growth :)
C)at week 4 the new factory exceed the old factory because new factory produce 337 products and old factory only produce 336.74.

Hope it will help:)

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Can someone please help me

salantis [7]

Using Pythagorean theorem

$\\ \sf\longmapsto P^2=H^2-B^2$

$\\ \sf\longmapsto P^2=6^2-5^2$

$\\ \sf\longmapsto P^2=36-25$

$\\ \sf\longmapsto P^2=11$

$\\ \sf\longmapsto P=3.2$

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2 years ago

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Use the function below to find F(3)

garik1379 [7]

Answer:

Theanswer is 4/27.

Step-by-step explanation:

given that, F(x) = 4×(1/3)^x

now , F(3)= 4×(1/3)^3 ( putting value of x)

or, F(3) = 4×(1/27)

therefore, F(3)= 4/27... ans

<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

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3 years ago

Henry records how many days he rides his bike and how far he rides each week. He rides the same distance each time . He rode 17

alexandr1967 [171]

64 miles cuz he would take the shorter way

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4 years ago

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HELP with Geometry PLEASES!! 100 points!!!

Igoryamba

Answer:

in order from images displayed, x = 20, x = 6, x = 5.5

Step-by-step explanation:

4x - 8 + 6x - 12 = 180

10x -20 = 180

10x = 200

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5x - 1 = 29

5x = 30

x = 6

14x - 6 = 12x + 5

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5 0

2 years ago

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Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f

Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

$Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\$

Subtracting Eqn 3 from Eqn 1;

$(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5$

Putting value of y in Eqn 1;

$300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9$

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

#LearnwithBrainly

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3 years ago