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cricket20 [7]
3 years ago
12

an amount of R3000, Is invested to three years at simple interest rate and it earned R905 interest. determine the simple interes

t rate at which the money was invested​
Mathematics
1 answer:
dusya [7]3 years ago
8 0

Answer:

Step-by-step explanation:

P=R3000.00

T=3 years

SI=R905

SI=P\times R\times T\\R905=R3000\times \frac{r}{100}\times 3SI=P×R×T

R905=R3000×  

100

r

​

×3

R905=\frac{R9000r}{100}R905=  

100

R9000r

​

 

R905=\frac{R905}{R90}R905=  

R90

R905

​

 

r=\frac{R905}{R90.}r=  

R90.

R905

​

 

r=10.06\%r=10.06%

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Expand and simplify (√10-√2)² Give your answer in the formn b-c√5 where b and c are integers
vesna_86 [32]

Answer:

12-4√5

Step-by-step explanation:

(√10-√2)²

(√10-√2)(√10-√2)

Foil/distribute

10-√20-√20+2

12-2√20

12-2√4*√5

12-2*2√5

12-4√5

5 0
2 years ago
Find the term indecent of x in the expansion of (x^2-1/x)^6
Mars2501 [29]

By the binomial theorem,

\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0   ===>   3k = 12   ===>   k = 4

which corresponds to the constant coefficient

\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}

3 0
3 years ago
In the distribution, the first quartile,median and mean are 30.8,48.5 and 42.0 respectively. If the co efficient skewness is -0.
finlep [7]

Answer:

The third quartile is 56.45

Step-by-step explanation:

The given parameters are;

The first quartile, Q₁ = 30.8

The median or second quartile, Q₂ = 48.5

The mean, \bar x = 42.0

Coefficient of skewness = -0.38

The Bowley's coefficient of skewness (SK) is given as follows;

SK = \dfrac{Q_3 + Q_1 - 2 \times Q_2}{Q_3 - Q_1}

Plugging in the values, we have;

-0.38 = \dfrac{Q_3 + 30.8 - 2 \times 48.5}{Q_3 - 30.8}

Which gives;

-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5

11.704 - 0.38·Q₃ = Q₃ - 66.2

1.38·Q₃ = 11.704 + 66.2 =  77.904

Q₃ = 56.45

The third quartile = 56.45.

5 0
3 years ago
Can u help me with this
Nesterboy [21]
A graphing calculator is a great help for problems of this nature.
  x ∈ {-5.63, -0.55, 2.59}

4 0
3 years ago
The difference between the most hours of sleep and the least of these students was 2.5 hours. True or false?​
SashulF [63]

The correct anwer is False

Explanation

According to the graph, it can be seen that a student has four hours of sleep as the minimum number of hours of sleep; two students have six hours of sleep, four students have six and a half hours of sleep, four have seven hours of sleep, three have seven and a half hours of sleep, five have eight hours of sleep, and one has eight and a half hours of sleep as maximum hours of sleep. Therefore, it can be affirmed that the statement that the difference between the maximum amount and the minimum number of hours is two and a half hours is false because between four hours and eight and a half hours there are four and a half hours of difference. So, the correct answer is False.

8 0
3 years ago
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