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Otrada [13]
3 years ago
7

What type of association is shown by the scatterplot?

Mathematics
2 answers:
Inessa [10]3 years ago
4 0

Answer: The answer is A

Step-by-step explanation: I took the test and it was right!

I hope this helped!

Basile [38]3 years ago
3 0

Answer:

A. linear, strong

Step-by-step explanation:

just got it right on edge 2020

Please mark as Brainliest

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The graph of an equation has a minimum y value of 12. This minimum occurs at an x value of 3. What is true of the graph of the e
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Answer:

i don't know

Step-by-step explanation:

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2 years ago
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Mike walked 3 miles in 45 minutes. What was his rate in miles per hour? Please show how you got your answer
amid [387]

Answer:

4 miles per hour

Step-by-step explanation:

We can divide 45 minutes by 3 to get 15 minutes:

So that is 1 mile in 15 mins

Then we multiply both sides by 4 to get 60 mins:

4 miles in 60 mins

So his rate was 4 miles per hour

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I need a lot of help What is <br> 89/2?
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Answer:

44.5

is the answer

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2 years ago
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en una caja hay 8 canicas cinco rojas y tres verdes y la Bola que se retira no se reemplaza determina Cuál es la probabilidad de
postnew [5]

Answer: 0.107

Step-by-step explanation:

En una caja tenemos 8 canicas.

5 son rojas

3 son verdes.

Se retira una canica, y no se remplaza.

Quiero calcular la probabilidad de sacar dos canicas verdes.

La probabilidad de sacar una canica verde en el primer intento, es igual al cociente entre el numero de canicas verdes y el numero total de canicas.

p1 = 3/8  

Ahora, en el segundo intento, en la caja voy a tener 2 canicas verdes (por que ya saque una) y 7 canicas en total. Entonces la probabilidad va a ser:

p2 = 2/7.

Y la probabilidad conjunta (es decir, la probabilidad de sacar las dos canicas de color verde) va a ser igual al producto de las probabilidades individuales.

P = p1*p2 = (3/8)*(2/7) = 0.107

8 0
2 years ago
4. Sherman hopes to get at least a 90 average on his science tests. He has one more test
Alinara [238K]

Answer:

79+94+91+92+test5)/5=90

The lowest score have to be 94

Step-by-step explanation:

Our goal is gona be to have an average of 90, it can be higher but we are going to use this.

For average the equation is

(test1+test2+test3+test4+test5)/5=average

We know the result for the first 4 tests

Test 1=79

Test 2=94

Test 3=91

Test 4=92

But we dont know test 5

(79+94+91+92+test5)/5=average

Our goal for the average is 90

(79+94+91+92+test5)/5=90

79+94+91+92+test5=90*5

test5=450-79-94-91-92

Test5=94

8 0
2 years ago
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