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zhuklara [117]
2 years ago
11

1.) Distance formula Find the distance between the pair of points.

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
8 0

Answer:

5

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (-1, 0) and (x₂, y₂ ) = (3, - 3) ← coordinates of endpoints

d = \sqrt{(3+1)^2+(-3-0)^2}

  = \sqrt{4^2+(-3)^2}

  = \sqrt{16 +9} = \sqrt{25} = 5

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steposvetlana [31]

Answer:

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Step-by-step explanation:

8 0
3 years ago
How can you identify a geometric sequence as an equation?​
Kipish [7]
The r-value, or common ratio, can be calculated by dividing any two consecutive terms in a geometric sequence.
7 0
2 years ago
A relay team ran a race. Each team member ran #1/4# of the distance. The whole race was #8/9# mile. How far did each team member
Andre45 [30]
Each member ran 2/9 miles
5 0
3 years ago
Mike earns $15 for each hour he works plus a $25 bonus. Represent this story in function notation
Kitty [74]

Answer:

y=15x +25

Step-by-step explanation:

Every hour he works, he get 15 dollars in addition to his bonus of 25 dollars

4 0
3 years ago
Read 2 more answers
Graph the image of the given triangle after the transformation with the rule (x, y)→(x−6, y−4) .
zaharov [31]

Answer: See the figure attached.

Step-by-step explanation:

Observe the figure attached. The vertices of the triangle ABC have the following coordinates:

A(2,5); B(6,2) and C(3,-5)

To graph the image (in this case we can identify it as A'B'C'), you must use the rule (x,y)→(x-6,y-4).

Then, you have to subtract 6 units from the x-coordinate of each vertex and subtract 4 units from the y-coordinate of each vertex.

Therefore, you get:

Vertex A'→ (2-6,5-4)=(-4,1)

Vertex B'→ (6-6,2-4)=(0,-2)

Vertex C'→ (3-6,-5-4)=(-3,-9)

Having the vertices of the image A'B'C', you can graph it (See the figure attached).

7 0
3 years ago
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