All categories

2 years ago

Help pleaseeeeeeeeee

Mathematics

1 answer:

harkovskaia [24]2 years ago

4 0

97+x=27+64
x=27+64-97
x=-6

(Hopefully this is correct)

You might be interested in

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

Solve the inequality. Graph the solution. −6n>54

AysviL [449]

Answer:

n<-9

us an open circle on -9 pointing to the left

hope this helps

have a good day :)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

COMPETE Answer as a dec 2.8+7.22 DONE

Vadim26 [7]

Answer:

Hi, there my name is 1frogaroni and I will be helping you out today!

Step-by-step explanation:

The answer to your question is 10.02.

2.8+7.22

=2.8+7.22

=10.02

You must simplify. if this helped I would be happy to get brainliest in order for me to rank up.

Have a great day!

3 0

3 years ago

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How m

exis [7]

Answer:

a) Write a let statement below to define your variable(s):

Let the number of fishes Ms. Montesinos has be represented by = f

b) Set up an equation using the variable you defined in (a):

The equation is :

3f - 2 = 13

c) Solve your equation & Check. How many fish does Ms. Montesinos have?

Ms. Montesinos has 5 fishes

Step-by-step explanation:

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How many fish does Ms. Montesinos have in her tank?

a) Write a let statement below to define your variable(s):

Let the number of fishes Ms. Montesinos has be represented by = f

b) Set up an equation using the variable you defined in (a):

We are told in the question:

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has.

Therefore,

3× f - 2 = 11 + 2

The equation is :

3f - 2 = 13

c) Solve your equation & Check. How many fish does Ms. Montesinos have?

Solving the above equation:

3f - 2 = 13

3f = 13 + 2

3f = 15

Divide both sides by 3

3f/3 = 15/3

f = 5

Hence, Ms. Montesinos has 5 fishes

4 0

3 years ago

A delivery truck drove 203 mi in 3.5 h. After unloading and loading new cargo, it traveled on another 243 mi for 4.5 h. What was

Ray Of Light [21]

The answer is number 1.
203+243=446
3.5+4.5=8
446/8= 55.75

5 0

3 years ago