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PilotLPTM [1.2K]
3 years ago
7

#3 only timed test!!

Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:

It's the second option

Step-by-step explanation:

When inputting each of those numbers given in the question into the equation, you get the numbers in the second option.

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#1 plz thx!!!!!!!!!!
r-ruslan [8.4K]
We have to use pythagorean theorem. The equation is a^{2} + b^{2} = c^{2} so we plug in the numbers (hypothenuse is always C in the equation) a^{2} + 8^{2} =10^{2} now we solve:

a^{2} +64=100 Exponents 

a^{2} =36 Subtract

a=6 Square Root

x=6 Answer
5 0
3 years ago
Compute​ P(x) using the binomial probability formula. Then determine whether the normal distribution can be used to estimate thi
stich3 [128]

Answer:

The answers to the questions are;

A) P(X) where x = 12 is equal to 3.55 ×10⁻²

B) P(x) using the normal distribution is given by the probability distribution function and is equal to 3.453 ×10⁻²

C) The calculated probabilities of P(x=12) using the binomial probability formula and the probability distribution function differ by 9.7×10⁻⁴

D) The normal distribution be used to approximate this probability because     a. because np(1-p) %u2265 ⇒ np(1-p) ≥ 10

E) c. the value of fi represents the expected proportion of observation less than or equal to the ith data value.

Step-by-step explanation:

To solve the question, we note that

n = 58

p = 0.3

x = 12

Here we have n·p = 17.4 and n·q = 40.6 both ≥ 5 that is the normal distribution can be used to estimate the probability

A) We are to use the binomial probability formula to find P(X)

Where x = 12, we have P(12) = ₅₈C₁₂×0.3¹²×0.7⁴⁶

= 891794789340×0.000000531441×7.49×10⁻⁸ = 3.55 ×10⁻²

B) Using the standard distribution table we have

the z score for x = 12 given as z = \frac{x-\mu}{\sigma} = -1.55

From the normal distribution table, we have the probability that value is below 12 = .06057 while the normal probability distribution function which gives the probability of a number being 12 is given by

\frac{1}{\sigma\sqrt{2 \pi } } e^{\frac{-(x-\mu)^2}{2\sigma^2} }

where:

σ = Standard deviation = \sqrt{npq} = \sqrt{np(1-p)} = \sqrt{58*0.3*(1-0.3)} = 3.48999

μ = Sample mean = n·p = 58×0.3 =17.4

Therefore the probability density function is \frac{1}{3.49\sqrt{2 \pi } } e^{\frac{-(12-17.4)^2}{2*3.49^2} } = 3.453*10^{-2}

C)  The probabilities differ by 3.55 ×10⁻² -  3.453 ×10⁻² =  9.7×10⁻⁴

D) The normal distribution be used to approximate this probability because     n·p and n·p·(n-p) ≥ 5

E)   f_i represents the area under the curve towards left of the ith data observed in a normally distributed population.

Therefore, the value of fi represents the expected proportion of observation less than or equal to the ith data value  

5 0
3 years ago
What is the area of a cross section that is parallel to face ABCD ?
Hunter-Best [27]
To solve this problem you must apply the proccedure shown below:
 1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
 A=12 cm x 6 cm
 2. Therefore, the result is:
 A=72 cm</span>²
 The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
3 0
3 years ago
Helpppp me plz any help would work :)
mixer [17]

Answer:

2d+3 dollars

Step-by-step explanation:

the second one 2d+3

7 0
3 years ago
Read 2 more answers
Does anyone know this
Tamiku [17]

Answer:

I belive the answer is A

Step-by-step explanation:

So any answer with 22t would make sense, so you have A and C. In C though, it is subtracting 22, but since 6195 is the total it would have to include the 22 so it is A.

8 0
3 years ago
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