If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is _.

1 answer:

defon3 years ago

8 0

Answer: If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is its conjugate 7-i5.

Step-by-step explanation:

We know that when a complex number $z=a+ib$ is a root of a polynomial with degree 'n' , then the conjugate of the complex number ( $\overline{z}=a-ib$ ) is also a root of the same polynomial.

Given: 7+5i is a zero of a polynomial function of degree 5 with coefficients

Here, 7+5i is a complex number.

So, it conjugate ( $\overline{7+5i}=7-5i$ ) is also a zero of a polynomial function.

Hence, if 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is its conjugate 7-i5.

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3 years ago

Read 2 more answers

How can 1/5x − 2 = 1/3x + 8 be set up as a system of equations? a . 5y − 5x = −10. 3y − 3x = 24 b. 5y − 5x = −10. 3y + 3x = 24 c

VMariaS [17]

The answer is d. 5y − x = −10. 3y − x = 24

$\frac{1}{5}x-2= \frac{1}{3}x+8=y$
⇒    $y= \frac{1}{5}x-2$
   $y= \frac{1}{3}x+8$
________________________
$y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}$
$y= \frac{x}{3} +8= \frac{x}{3} + \frac{24}{3} = \frac{x+24}{3}$
________________________
$y= \frac{x-10}{5}$ ⇒    $5y=x-10$
$y= \frac{x+24}{3}$   ⇒    $3y=x+24$
________________________
$5y-x=-10$
$3y-x=24$

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3 years ago

If 3x - 2y = 9 , 27x³- 8y³= 1377 , prove that xy = 4 plzz answer this question...

solniwko [45]

Step-by-step explanation:

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