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3 years ago

3xsquare-9x-30=0 What’s the answer

Mathematics

1 answer:

BartSMP [9]3 years ago

6 0

Answer:

x = - 2 or x = 5

Step-by-step explanation:

Given

3x² - 9x - 30 = 0 ← in standard form

Divide all terms by 3

x² - 3x - 10 = 0

To factor the quadratic

Consider the factors of the constant term (- 10) which sum to give the coefficient of the x- term (- 3)

The factors are - 5 and + 2, since

- 5 × 2 = - 10 and - 5 + 2 = - 3, thus

x² - 3x - 10 = 0

(x - 5)(x + 2) = 0

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 2 = 0 ⇒ x = - 2

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Find the weight of the cast iron shape shown below at 0.26 pounds per cubic inch. (round to the nearest pound). The height of th

weqwewe [10]

Answer:

640 pounds

Step-by-step explanation:

The rest of the question is the attached figure

So, the total volume = V(cylinder ) + V(cone)

The volume of cylinder = π r² h

The volume of cone = π r² h/3

Both of the cylinder and the cone have the same diameter = 14 inches

So, the radius = 14/2 = 7 inches

The height of the cylinder is 13 inches and the height of the cone is 9 inches.

So, The volume of cylinder = π r² h = π * 7² * 13 = 2,001.2 in³

And The volume of cone = π r² h/3 = π * 7² * 9/3 = 461.8 in³

So, the total volume = 2,001.2 + 461.8 = 2,463 in³

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3 years ago

Solve the inequality r/6 < or equal to 3

RSB [31]

R is greater then or equal to18

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3 years ago

What is the value of 24x -60

Aleksandr [31]

Answer:

-1440

Step-by-step explanation:

24x -60 = -1440

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2 years ago

What is a equation in point slope form for a line perpendicular to y=-4x-10 that contains (1,-5)

mixas84 [53]

Y = 1/4x -5

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3 years ago

I NEED THIS ASAP, PLEASE HELP!!!

WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0

3 years ago