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3 years ago

What is the answer to the problem 16g +20h with the distributed property applied

Mathematics

2 answers:

e-lub [12.9K]3 years ago

8 0

36 g I’m pretty sure that’s the answer

allsm [11]3 years ago

7 0

Answer:

4(4g +5h)

Step-by-step explanation:

The GCF (greatest common factor) of the coefficients 16 and 20 is 4, meaning they are both divisible by 4. When you distribute the GCF to these numbers you get the following:

4(4g + 5h)

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3 years ago

A plane flying at a certain altitude is observed from two points that are 2.2 meters apart. The angles of elevation made by the

lana [24]

$tan(72)= \frac{y}{x} ; tan(55)= \frac{y}{2.2 + x}$
$y=xtan(72);y=(2.2+x)tan(55)$
So we are to merge the two equations into one, since both of the equations are equal to y. a = b, b = c therefore, a = c.
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3 years ago

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larisa [96]

Answer

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Step-by-step explanation:

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4 years ago

Read 2 more answers

34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$ .

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

$m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$ , and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

$y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$ , and simplify as follows,

$y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$$

This is the required linear equation.

5 0

2 years ago

What is the answer to the problem 16g +20h with the distributed property applied​

What is the answer to the problem 16g +20h with the distributed property applied