Shanna attends school for 1 week longer than 3/4 of the year. How many weeks in a year does Shanna attend school?
2 answers:
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<h3>Answers:</h3><h3>a. Vertices of triangle ABC are: A, B, C</h3><h3>b. Sides of triangle ABC are: AB, BC, AC</h3><h3>c. The side between angle A and angle C is: side AC</h3><h3>d. The angle between sides AB and CA is: angle A</h3><h3>e. Scalene triangle</h3>
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Explanations:
- a. Each uppercase letter represents a point or angle of the triangle.
- b. Connect two points of a triangle and you get a line segment. The order of the letters does not matter. So AB is the same as BA.
- c. Like with part b, connecting two angles or points forms a segment.
- d. Note how the letter "A" is in both AB and CA, so this is the shared angle between the two segments.
- e. Sides AB, BC, and AC are all different lengths, so we have a scalene triangle. If you had two sides equal to each other, then you'd have an isosceles triangle. If all three sides are equal, then it would be equilateral.
There is no need for a diagram, but if you want, you can draw one out. See the attached image below for the diagram. This diagram should hopefully answer any questions you may have about the explanations above. There are many ways to draw the triangle, so your diagram might look different from mine.
Answer:
a)
b)
c)
Sicne this probability just represent 1% of the data we can consider this value as unusual.
d)
And if we solve for a we got
So the value of height that separates the bottom 90% of data from the top 10% is 87360.
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:
Where and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using excel or the normal standard table and we got:
Part b
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the complement rule and excel or the normal standard table and we got:
Part c
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the complement rule and excel or the normal standard table and we got:
Sicne this probability just represent 1% of the data we can consider this value as unusual.
Part d
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
So the value of height that separates the bottom 90% of data from the top 10% is 87360.
Answer:
tanΘ = -
Step-by-step explanation:
Using the trigonometric identities
• sin²x + cos²x = 1, hence
cosx = ± √(1 - sin²x )
• tanx =
given sinΘ = , then
cosΘ = ±
Since Θ is in the second quadrant where cosΘ < 0, then
cosΘ = -
= - = -
tanΘ =
= × -
= -
Answer:
0.8%.
Step-by-step explanation:
Given:
At the start of the month, the value of an investment was $73.42.
By the end of the month, the value of the investment changed by a loss of $13.53.
Question asked:
What was the value, in dollars, of the investment at the end of the month?
What was the percent loss?
Solution:
At the start of the month, the value of an investment = $73.42.
Loss = $13.53.
<u><em>The value, of the investment at the end of the month = The value of an investment at the start of the month - loss</em></u>
The value, of the investment at the end of the month = $73.42 - $13.53
= $59.89
Thus, the value, of the investment at the end of the month is $59.89.
Now, we will find percent loss:-
Thus, percent loss on investment by the end of the month is 0.8%.