Answer:
<em>The student completed 13 courses worth 3 credits</em>
Step-by-step explanation:
<u>System of Equations</u>
Let's assign the following variables:
x = number of courses worth 3 credits
y = number of courses worth 4 credits
Some student completed 18 courses thus:
x + y = 18 [1]
The student earned a total of 59 credits:
3x + 4y = 59 [2]
From [1]:
y = 18 - x
Substituting in [2]:
3x + 4(18 - x) = 59
Operating:
3x + 72 - 4x = 59
Simplifying:
-x = 59 - 72 = -13
x = 13
The student completed 13 courses worth 3 credits
Answer:
12
Step-by-step explanation:
Answer:
Correct option is
B
1.x+0.y=7
x=7 can be written as, 1.x+0.y=7 as the coefficient of x is 1 and that of y is 0. Step-by-step explanation:
What this setup essentially represents is “How many 8s can we take away from 32 before hitting 0?” Which in turn can be reframed as “How many 8s fit into 32?” This can be captured in the expression 32 / 8. As we can see from the problem, we can take away 4 8’s before hitting 0, so that gives us the equation 32 / 8 = 4
9.09 I'm pretty sure this it