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PIT_PIT [208]
3 years ago
13

Ilke is deciding whether to take his girlfriend on a dinner date or on a movie date. The probability of his having a successful

dinner date is 55%. The probability of his having a successful movie date is 0.45. Which of these events is more likely?
A.) Ilke has a successful dinner date.
B.) Ilke has a successful movie date.
C.) Neither. Both events are equally likely.
Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0

Answer:

the answer is Ilke has a successful dinner date.

Step-by-step explanation:

Trava [24]3 years ago
6 0

A.) llke has a successful dinner date

Because .45 out of 100 is 45%

So if youre trying to see which ones more likely, 45% or 55%. Its pretty obvious which one

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Use the elimination method to solve the system of equations. Choose the correct ordered pair<br>​
UkoKoshka [18]

Answer:

Answer is B

Step-by-step explanation:

12x - y = 25 \\ 9x + y = 17 \\ x =  \frac{17 - y}{9}  \\ 12( \frac{17 - y}{9} ) - y = 25 \\

\frac{204}{9}  -  \frac{12}{9} y - y = 25 \\  \frac{204}{9}  -  \frac{21y}{9}  = 25 \\  -  \frac{21y}{9}  = 25 -  \frac{204}{9}  \\  -  \frac{21y}{9} =  2.33 \\ - 21y =  20.997 \\ y =  - 0.99

y =  - 1 \\ x =  \frac{17 - y}{9}  \\ x =  \frac{17 -  - 1}{9}  =  \frac{18}{9}   \\ x = 2

5 0
3 years ago
The ratio of potatoes to turnips is 1:1 if there are 473 potatoes how many turnips are there
navik [9.2K]

Answer:

There would be 473 turnips.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Give the probability that the spinner shown would land on the indicated color:1) black
mel-nik [20]
There is not enough information to answer :(
5 0
4 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0
3 years ago
Graph f(x) = |x - 6| -4
LekaFEV [45]

Answer:

Step-by-step explanation:

Graph the parent function y = |x|.  This graph has a v shape with vertex at (0, 0) and opens up.

Now translate the entire graph 6 units to the right.  The vertex will now be at (6, 0).

Finally, translate this most recent graph 4 units down.  The vertex will now be at (6, -4).

4 0
3 years ago
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