Okay well
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t
now, find the half, set a(t)= half the original and solve for t
14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t
t=in(0.5)/(-0.1359)= (aprox) 5.1 days
6
25
49
256
1000
512
59049
512
81
2401
Answer:
The answer will be A <u>3/2=6/4</u>
Step-by-step explanation:
Hope this helps :)
Answer: 2.339
Step-by-step explanation:
Make sure that you align your decimal points. The 1 shouldn't line up with the 7.
Instead, write your equation like:
2.37
- 0.031
The numbers don't match up, but instead, the decimals do.
I hope this helps! :)
Ok here is what I think.
Let us first number these statements, as #1, and #2.
First statement: 3x + 8y = 12 (1)
Second Statement: 2x + 2y = 3 (2)
Now, we can work from this.
We want to make one of the equations be equal to 0 so that at the end when we check they can be equal to each other.
Let us use 4.
3x+8y=12 1-8x-8y=-12 2
This gives us:-5x = 0
Now we should try and isolate x so we can substitute it into one of the equations.
We have -5x=0
and x=0
3(0)+8y=12
8y=12
y=12/8
y=3/2
Plug in these new equations
y=3/2 and y=0 into any of the first equations
3x+8y=12 3(0)+8(3/2)= 12 8(3/2)=12 4(3)=12 12=12
Now we know it works, thats our check^^
