Answer: 27
Step-by-step explanation:
F(6)=42-15=27
So we have. The given problem for number 1!
Next we have problem 2 with the given values. Solved above.
Answer:
Solving Steps
Use the quadratic formula
Multiply / Remove the parentheses / Evaluate
Calculate
Separate the solutions
Simplify
The value of (1+tanx)(1-tanx)+sec²x is 0 and the value of is .
Given that, (1+tanx)(1-tanx)+sec²x.
Now, (1-tan²x)+sec²x
=1-tan²x+sec²x
=1+sec²x-tan²x
=1-1=0
Now, evaluate
(∵a²-b²=(a+b)(a-b))
Hence, the value of (1+tanx)(1-tanx)+sec²x is 0 and the value of is .
To learn more about trigonometric identities visit:
brainly.com/question/12537661.
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