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3 years ago

Which inequality statement describes the two numbers: -13 and a number 28 units to the right of -13?

2 answers:

7 0

So you have -13, then a number that's somewhere to the right of -13. imagine a number line: the negative values are on the left side of the zero, the positive values are on the right. if you're moving to the RIGHT of -13, that means that the value will be greater than -13, or in other words, -13 will be less than the new value because you moved right.

to find the number 28 units to the right of -13, you simply need to add these two numbers: -13 + 28. you add them because you're moving 28 units in the POSITIVE direction, aka you're going UP, so you want to add. -13 + 28 = 15.

now read the statements your question gave you. C and D are just straight-up false--a positive number is never less than a negative number. those are out immediately. now, the numbers you're working with are -13 and 15, so you can immediately ignore B as an answer choice, but still: A is correct because it shows the correct inequality. -13 is less than the number 28 units to the right of it, that number being positive 15.

Damm [24]3 years ago

3 0

I believe the answer is A

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2 years ago

What is the distance, d, between the points (3,5/2) and (5/3,1)?

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2 years ago

X to the power of 2 subtract 3x for x=4

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2 years ago

There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is

malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

$25,26,28,52,56,58,62,65,68,82,85,86$

Hence, the required numbers.

2) Recall that probability is the ratio:

$Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}$

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

$P(A)=\frac{9}{12}=\frac{3}{4}$

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

$P(B)=\frac{3}{12}=\frac{1}{4}$

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

$P(C)=\frac{0}{12}=0$

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

7 0

1 year ago