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fredd [130]
3 years ago
14

Which inequality statement describes the two numbers: -13 and a number 28 units to the right of -13?

Mathematics
2 answers:
kkurt [141]3 years ago
7 0
So you have -13, then a number that's somewhere to the right of -13. imagine a number line: the negative values are on the left side of the zero, the positive values are on the right. if you're moving to the RIGHT of -13, that means that the value will be greater than -13, or in other words, -13 will be less than the new value because you moved right.

to find the number 28 units to the right of -13, you simply need to add these two numbers: -13 + 28. you add them because you're moving 28 units in the POSITIVE direction, aka you're going UP, so you want to add. -13 + 28 = 15.

now read the statements your question gave you. C and D are just straight-up false--a positive number is never less than a negative number. those are out immediately. now, the numbers you're working with are -13 and 15, so you can immediately ignore B as an answer choice, but still: A is correct because it shows the correct inequality. -13 is less than the number 28 units to the right of it, that number being positive 15.
Damm [24]3 years ago
3 0
I believe the answer is A
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The given sequence is
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This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
a_{n}=a_{1}+(n-1)d
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a₃₃ = 29 + (33 - 1)*10
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3 years ago
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sergiy2304 [10]

Answer:

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Step-by-step explanation:

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Answer:

Two distinct real solutions.

Step-by-step explanation:

Given the equation in the form ax^2+bx+c=0, you need to find the Discriminant with this formula:

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a=-2\\b=5\\c=-3

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