DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
C. x = -12 and x = 2
Step-by-step explanation:
-x²-10x+24=0 Original equation
x²+10x-24=0 Divide everything by -1
(x+12)(x-2)=0 Factor it out
x=-12,2 Solve so that the inside of the parentheses equals 0
4/13.6 = 0
(X/3)/4 = 24
x^2-(7*x)+12 > 0
(1/2)*x^2 = -7
(1/3)*p^2 = 1/4
My friend did this one let me know if it's right or wrong. <3
Answer:
6/8
Step-by-step explanation:
simplify and find the slope
