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Fantom [35]
3 years ago
12

One of the cars are blue it van travel 31 1/2 miles on 1 1/4 gallons of gasoline .Another car is red it can travel 28 4/5 miles

on 4/5 gallon of gasoline what is the unite rate for miles per gallon for each car
Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

Step-by-step explanation:

One of the cars are blue. it can travel 31 1/2 miles on 1 1/4 gallons of gasoline. Converting 31 1/2 miles to decimal, it becomes 31.5 miles. Converting 1 1/4 gallons of gasoline to decimal, it becomes 1.25 gallons of gasoline.

Therefore, the miles per gallon for the blue car is

31.5/1.25 = 25.2 miles per gallon.

Another car is red it can travel 28 4/5 miles on 4/5 gallon of gasoline.

Converting 28 4/5 miles to decimal, it becomes 28.8 miles. Converting 4/5 gallons of gasoline to decimal, it becomes 0.8 gallons of gasoline.

Therefore, the miles per gallon for the red car is

28.8/0.8 = 36 miles per gallon.

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A square also has four right angles. Therefore, a square is a type of rectangle.

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Write a system of equations to describe the following scenario:
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3 years ago
A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L
Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider \Delta ABC as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}

From the given data, L=15\:ft=AC, y=9\:ft=AB and x=BC

Substituting the values,  

\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}

\therefore 81+x^{2}=225

\therefore x^{2}=225-81

\therefore x^{2}=144

\therefore \sqrt{x^{2}}=\sqrt{144}

\therefore x=\pm 12

Since length can never be negative, so x= 12.

Now to calculate \dfrac{dy}{dt} again consider following equation,  

\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}

Differentiate both sides of the equation with respect to t,  

\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)

Applying sum rule of derivative,

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)

Applying power rule of derivative,  

2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0

Simplifying,  

y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0

Substituting the values,  

9\dfrac{dy}{dt}+12\times1.5=0

9\dfrac{dy}{dt}+18=0

Subtracting both sides by 18,

9\dfrac{dy}{dt}=-18

Dividing both sides by 9,

\dfrac{dy}{dt}= - 2

Here, negative indicates that the ladder is sliding in downward direction.  

\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}

7 0
3 years ago
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