Answer:
The Chef will prepare 320 soups for a large banquet
Step-by-step explanation:
chef thinks that 2 out of every 5 dinner guests will order soup
===> Order soup / total number of attender
= 2/5
Total guest = 800 ==> 4 people ordered soup is
2 /5 = x /800
cross multiplying
x = 2 x 800 / 5
= 320
The Chef will prepare 320 soups for a large banquet
Answer:
least to greatest : 14/9 , sqrt 7, sqrt 13, sqrt 40, 4^3
Step-by-step explanation:
Answer:
a) P(t>3)=0.30
b) P(t>10|t>9)=0.67
Step-by-step explanation:
We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.
The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.
The probabity that a repair time exceeds k hours can be written as:

(a) the probability that a repair time exceeds 3 hours?

(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?
The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.
In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.


Answer:
I believe the answer would be 4,5,6.
Step-by-step explanation: