If 5 is the base, 3(x-1) is the argument:
3x-1=5²
3x=26
x=26/3
If 5 is with 3x-1, that is, if 5(3x-1) is the argument, and the base is 10:
5(3x-1)=10²
3x-1=20
3x=21
x=7
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3.
Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then
A(Y) = 2A(X)
[T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3
But [T(X)]^2 = [A(X)]^3
Thus [T(Y)]^2 = 2^3[T(X)]^2
[T(Y)]^2 / [T(X)]^2 = 2^3
T(Y) / T(X) = 2^3/2
Therefore, the orbital period increased by a factor of 2^3/2
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<span>1 x + 1 y = 7 .............1
Total value
15 x + 28 y = 131 .............2
Eliminate y
multiply (1)by -28
Multiply (2) by 1
-28 x -28 y = -196
15 x + 28 y = 131
Add the two equations
-13 x = -65
/ -13
x = 5
plug value of x in (1)
1 x + 1 y = 7
5 + y = 7
y = 7 -5
y = 2
y = 2
x= 5 plain shirts
y= 2 fancy shirts </span>
Step-by-step explanation:
First you must simplify the equation:
subtract 1 from both sides:
than divide both sides by -3, which switches the inequality sign:
This inequality means that all values of x greater than -2 work for the equation. because it is not 
, -2 is not included, so there will be a hollow circle there. than the inequality will have a line from that dot to the right so that all values of x that work for the inequality are on that line.
