2 years ago

Please help worth alot of pts just 1 question

Mathematics

2 answers:

zhenek [66]2 years ago

8 0

The triangle ABC is an isosceles triangle.

∴ ∠BAC = ∠BCA and hence ∠BCA = ∠CAD.

Since the alternate angles BCA and CAD are equal, BC║AD.

vekshin12 years ago

7 0

Sense BC = AD

AD = BC

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sp2606 [1]

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Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

Prologarithmize both parts of the equation:

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

Divide both parts of the equation by 2:

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

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