The table below shows the number of Japanese yen that could be exchanged for U.S. dollars on the day

Professor wonders whether a student's homework average (X) could be used to predict their final grade in the course (Y) . She ca

Anna11 [10]

Answer:

The dependent variable is the final grade in the course and is the vriable of interest on this case.

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

Step-by-step explanation:

On this case w ehave the following linear model:

$Y= 21.839 +0.724 X$

Where Y represent the final grade in the course and X the student's homework average. For this linear model the slope is given by $\beta_1 = 0.724$ and the intercept is $\beta_0 = 21.839$

Which is the dependent variable, and why?

The dependent variable is the final grade in the course and is the vriable of interest on this case.

Based on the material taught in this course, which of the following is the most appropriate alternative hypothesis to use for resolving this question?

Since we conduct a regression the hypothesis of interest are:

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

3 0

2 years ago

3xy + 5 if x = -4, y = 2

Zanzabum

Answer:

it will be -19

Step-by-step explanation:

i hope it helps you

7 0

2 years ago

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What is the<br> proprtion?

KengaRu [80]

In mathematics, two varying quantities are said to be in a relation of proportionality, if they are multiplicatively connected to a constant; that is, when either their ratio or their product yields a constant. The value of this constant is called the coefficient of proportionality or proportionality constant.

7 0

3 years ago

One of the roots of the equation x²-5x +q=0 is 2. Find the other root and the value of the coefficient q.

yuradex [85]

Answer:

Other root: $x=3$

$q=6$

Step-by-step explanation:

If $x=2$ , then $x-2=0$ .

Therefore:

$x^2-5x+q=0$

$2^2-5(2)+q=0$

$4-10+q=0$

$-6+q=0$

$q=6$

This means that the other root is $x=3$ since $(x-2)(x-3)=x^2-5x+6$

5 0

2 years ago

Which table represents a quadratic relationship?

svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0

3 years ago

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