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3 years ago

Which expression is equivalent to m − 20? (5 points) 5(m − 100) 5(m − 4) (m − 100) (m − 4)

Mathematics

1 answer:

Anna11 [10]3 years ago

7 0

The answer will be 5(m-100) because 5m-100 equal to m-20 which you just need to divided 5. Hope it help!

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A 3-column table with 3 rows. Column 1 is labeled Vehicle with entries Sedan, Minivan, Truck. Column 2 is labeled Miles Traveled

Alexus [3.1K]

Answer:

Step-by-step explanation:

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4 years ago

-6 > -9 Which best explains whether the inequality is true or false?

Natali [406]

Answer:

-6 on a number line is closer to 0 which make sit greater while -9 is farther away which makes it less than -6

Step-by-step explanation:

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3 years ago

Read 2 more answers

sammi is trying to wrap a gift for her brother. the gift fits into a cube-shaped box with a side length of 9 inches. how many sq

Flauer [41]

Answer:

$A=486\ \text{inches}^2$

Step-by-step explanation:

The area of a cube shaped box is given by :

$A=6s^2$

Where

s is the side length and A is the surface area

We have, s = 9 inches

So,

$A=6\times (9)^2\\\\A=486\ \text{inches}^2$

So, the required area is $486\ \text{inches}^2$ .

8 0

3 years ago

Plz answer both if you can

Harlamova29_29 [7]

I hope this helps you

130+x-5+x-35+x+30+75=360

3x=360-195

3x=165

x=55

m (B)=55-5=50

7 0

3 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

6 0

4 years ago