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denpristay [2]
3 years ago
8

Which expression is equivalent to m − 20? (5 points) 5(m − 100) 5(m − 4) (m − 100) (m − 4)

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0
The answer will be 5(m-100) because 5m-100 equal to m-20 which you just need to divided 5. Hope it help!
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A 3-column table with 3 rows. Column 1 is labeled Vehicle with entries Sedan, Minivan, Truck. Column 2 is labeled Miles Traveled
Alexus [3.1K]

Answer:

50

Step-by-step explanation:

3 0
4 years ago
-6 &gt; -9<br><br> Which best explains whether the inequality is true or false?
Natali [406]

Answer:

-6 on a number line is closer to 0 which make sit greater while -9 is farther away which makes it less than -6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
sammi is trying to wrap a gift for her brother. the gift fits into a cube-shaped box with a side length of 9 inches. how many sq
Flauer [41]

Answer:

A=486\ \text{inches}^2

Step-by-step explanation:

The area of a cube shaped box is given by :

A=6s^2

Where

s is the side length and A is the surface area

We have, s = 9 inches

So,

A=6\times (9)^2\\\\A=486\ \text{inches}^2

So, the required area is 486\ \text{inches}^2.

8 0
3 years ago
Plz answer both if you can
Harlamova29_29 [7]
I hope this helps you



130+x-5+x-35+x+30+75=360


3x=360-195


3x=165


x=55


m (B)=55-5=50
7 0
3 years ago
Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

6 0
4 years ago
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