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tester [92]
4 years ago
15

Help me solve this problem

Mathematics
1 answer:
Alexxx [7]4 years ago
3 0

Answer:

C. Associative Property

Step-by-step explanation:

The associative property of addition states that changing the grouping of the addends does not change the sum.

(-7+3)= -4

-4+9= 5

(3+9)= 12

-7+12=5

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The lengths in feet of three pieces of timber are
Sonbull [250]

The equal length of the logs will be 200 feets each.

Since the lengths in feet of three pieces of timber are 144, 216, 240 and the operator wants to cut them into 3 equal sizea, this will go thus:

= (144 + 216 + 240) / 3

= 600/3

= 200 feets each

Therefore, there'll be an equal length of 200 feets each.

Read related link on:

brainly.com/question/24664848

7 0
3 years ago
Freddy is searching for a shirt and discovers that he has 12 shirts for every 6 pair of jeans.If he has 18 shirts, how many pair
KIM [24]
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6 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Y=-3x+5 5x-5y=-3by substitution​
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Answer:

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Step-by-step explanation:

the question is already substituted

5 0
3 years ago
PLSS HELP WILL GIVE BRAINLIEST TIMED QUESTION<br><br> What is m
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Answer:

Step-by-step explanation:

The answer is 46

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