Find 5 consecutive numbers whose sum is 65.

Mathematics

2 answers:

kodGreya [7K]3 years ago

8 0

Answer:

11, 12, 13, 14 and 15.

Step-by-step explanation:

This is because these numbers are consecutive and add up to 65

PLEASE GIVE BRAINLIEST

ExtremeBDS [4]3 years ago

4 0

Answer:

11 + 12 + 13 + 14 + 15 = 65

consecutive numbers are numbers that don't have gaps in between

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$x \geq 96, x\in\mathbb{R}\\ x\ \textless \ 38, x\in\mathbb{R}$

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olasank [31]

Hello,

$u_{1} =4\\
 u_{2} =4*q\\
 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
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if \ q=-2 \ then\ \sum_{i=0}^{8}\ 4*(-2)^i= 4*\dfrac{1-(-2)^9}{1+2} =684\\



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