I need help asapp!!!!!!!
1 answer:
Answer:
Step-by-step explanation:
As per midsegment theorem of a trapezoid,
Segment joining the midpoints of the legs of the of the trapezoid is parallel to the bases and measure half of their sum.
Length of midsegment =
3). MN =
= 14
4). MN =
= 66.5
5). MN =
7 =
14 = AB + 10
AB = 14 - 10
AB = 4
6). 15 =
30 = 5x
x = 6
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Answer:
0.3597 = 35.97% probability that roommate A wins the game and thus does not have to wash the dishes.
Step-by-step explanation:
Independent events:
If two events are independent, the probability of both happening is the multiplication of their probabilities.
Rock-paper-scissors rules:
A player that choose rocks beats one who chooses scissors.
A player that choose paper beats one who chooses rocks.
A player that choose scissors beats one who chooses paper.
Probability that roommate A wins the game and thus does not have to wash the dishes.
3 possible events:
Roommate A - Rocks(21% of the time) and Roommate B - Scissors(18% of the time)
So
Roommate A - Paper(39% of the time) and Roommate B - Rocks(61% of the time).
So
Roommate A - Scissors(40% of the time) and Roommate B - Paper(21% of the time).
So
Probability of roommate A winning:
0.3597 = 35.97% probability that roommate A wins the game and thus does not have to wash the dishes.
Answer:
y(t) = 3u₂(t) [ ] - 4u₅(t) [
]
Step-by-step explanation:
To find - y″+ 5y′ + 6y = 3δ(t − 2) − 4δ(t −5); y(0) = y′(0) = 0
Formula used -
L{δ(t − c)} =
L{f''(t) = s²F(s) - sf(0) - f'(0)
L{f'(t) = sF(s) - f(0)
Solution -
By Applying Laplace transform, we get
L{y″+ 5y′ + 6y} = L{3δ(t − 2) − 4δ(t −5)}
⇒L{y''} + 5L{y'} + 6L{y} = 3L{δ(t − 2)} − 4L{δ(t −5)}
⇒s²Y(s) - sy(0) - y'(0) + 5[sY(s) - y(0)] + 6Y(s) = 3 - 4
⇒s²Y(s) - 0 - 0 + 5[sY(s) - 0] + 6Y(s) = 3 - 4
⇒s²Y(s) + 5sY(s) + 6Y(s) = 3 - 4
⇒[s² + 5s + 6] Y(s) = 3 - 4
⇒[s² + 3s + 2s + 6] Y(s) = 3 - 4
⇒[s(s + 3) + 2(s + 3)] Y(s) = 3 - 4
⇒[(s + 2)(s + 3)] Y(s) = 3 - 4
⇒Y(s) =
Now,
Let
By Comparing, we get
A + B = 0 and 3A + 2B = 1
⇒A = -B
and
3(-B) + 2B = 1
⇒-B = 1
⇒B = -1
So,
A = 1
∴ we get
So,
Y(s) =
⇒Y(s) =
By applying inverse Laplace , we get
y(t) = 3u₂(t) [ ] - 4u₅(t) [
]
⇒y(t) = 3u₂(t) [ ] - 4u₅(t) [
]
It is the required solution.