A golfball is hit from ground level with an initial vertical velocity of 80 ft/s. Use the function h(t) = −16t2 + v0t + h0, wher
1 answer:
You might be interested in
<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes.
</span>In Step 1, Hannah wrote
<span> as the sum of two separate derivatives </span>
<span>using the </span><span>sum rule.
</span>
This step is perfectly fine.
In Step 2,
was kept as it is, and 
was rewritten as 
using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.
This step is perfectly fine.
In Step 3,
was rewritten as 
supposedly using the constant multiple rule.
The problem is that according to the constant multiple rule,
should be rewritten as 
and not as 
.
<span>Therefore, Hannah made a mistake in this step.</span>
</span>In Step 1, Hannah wrote
</span>
This step is perfectly fine.
In Step 2,
This step is perfectly fine.
In Step 3,
The problem is that according to the constant multiple rule,
<span>Therefore, Hannah made a mistake in this step.</span>
Answer:
-3.92 N
Step-by-step explanation:
We are given that
Mass of ball=0.4 kg
Acceleration due to gravity=
Because the ball flies against to gravity
We have to find the net force acting on the ball while it is in motion.
We know that when there is no air resistance then the net force acts on the ball is equal to weight of ball.
Net force,F =mg
Substitute the values then we get
Hence, the net force acting on the ball while it is on motion=-3.92 N
Answer:
Hello your question is incomplete below is the complete question
option B is correct
f(x) = 1 if x ≤ 0
-2 if x > 0
Step-by-step explanation:
The Rule of the piece-wise-defined function is :
from the given figure attached it can be seen that as : x ≤ 0 , y = 1
while for x > 0 , y = -2
therefore option B is correct
f(x) = 1 if x ≤ 0
-2 if x > 0
