Answer:
669 dollars and 70 cents
Step-by-step explanation:
just minus all the money spent and add the money added
The first thief takes (1/2 x + 1) . What remains ? x - (1/2x + 1)
So the 2nd thief takes 2/3 of [ x - (1/2x + 1) ]
What remains ? x - 2/3 [ x - (1/2x + 1) ]
So the 3rd thief takes 2/3 of { x - 2/3 [ x - (1/2x + 1) ] } and he takes 1 more .
What remains ? x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )
And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..
The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.
===============================================
This is a lot harder than just solving the problem with logic and
waving your hands in the air. Here's how you would do that:
Start from the end and work backwards:
-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.
Thank you for your generous 5 points.
So the answer should be 48.58 if not then it could be 278n
Answer: -4
Step-by-step explanation:
Solve 2x+7=-1
2x. =-8
x. =-4
Answer:
Step-by-step explanation:
<u>Informação recuperada:</u>
(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é
1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:
2) Aplicando a propriedade do produto de logaritmo:
3) Como quero o quociente divido ambos os lados por y
