Here, AB ║ CD ; EF ⊥ AB
Number of 90 degree formed by the intersections of EF and two parallel lines AB and CD is 8
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Answer:
So, the step1 is correct.
Step-by-step explanation:
The expression is

So, the step 1 is correct.
Answer: The answer is (B) ∠SYD.
Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.
We are given four angles, out of which one should be chosen which is congruent to ∠CXP.
The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.
For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.
Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.
Thus, we have
∠CXP ≅ ∠SYD.
So, option (B) is correct.
Answer:
Step-by-step explanation:
length of an arc(s) = θ/360 x 2πr
where θ is the central angle and r is the radius
Answer:
6. yes they are congruent, they are exactly the same shape and size
7. no they are not congruent, they are different sizes
8. they are congruent, they have the same shape and size
Step-by-step explanation: