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RUDIKE [14]
3 years ago
6

What is the value of m in the equation

{2}" alt="\frac{1}{2}" align="absmiddle" class="latex-formula">m - \frac{3}{4}n= 16, when n=8
Mathematics
2 answers:
Novosadov [1.4K]3 years ago
6 0

Answer:

The value of m is 44

Step-by-step explanation:

We have given:

1/2 m - 3/4 n = 16

Put the value of n in the given equation

1/2m - 3/4(8)=16

Now 4 and 8 will be canceled out by the table of 4

1/2 m - 3(2)=16

1/2m - 6 = 16

Now take the L.C.M of the denominator and solve for numerator:

m-2(6)/2 = 16

m-12/2 = 16

m-12 = 16*2

m-12 = 32

Add 12 at both sides:

m-12+12 = 32+12

m= 32+12

m=44

The value of m is 44....

Levart [38]3 years ago
6 0

Answer: m=44

Step-by-step explanation:

You have the following equation:

\frac{1}{2}m - \frac{3}{4}n= 16

In order to know the value of "m" when the value of "n" is 8 (n=8), you have to substitute this value into the equation and solve for "m".

Therefore, you get:

\frac{1}{2}m - \frac{3}{4}n= 16\\\\\frac{1}{2}m - \frac{3}{4}(8)= 16\\\\\frac{1}{2}m - \frac{24}{4}= 16\\\\\frac{1}{2}m - 6= 16\\\\\frac{1}{2}m = 16+6\\\\\frac{1}{2}m =22\\\\m=(2)(22)\\\\m=44

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torisob [31]

The number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles

The Company A rented the truck for $40 a day plus $0.40 per miles

The expression will be

40+0.40x

Where x  is the number of miles

The company B rented the truck for $20 a day plus $0.50 per miles

20+0.50x

To find the number of miles in a day at which the rental costs for Company A and Company B are the same, the linear equation will be

40+0.40x = 20+0.50x

40-20 = 0.50x-0.40x

0.1x = 20

x = 200 miles

Hence, the number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles

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1 year ago
Whats the perimeter and area of this shape?
stich3 [128]

Answer:

<u>60+14.35=88.27</u>

Step-by-step explanation:

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rusak2 [61]

Answer:

(1.13, 7.74) and (-4.13, 18.26)

Step-by-step explanation:

This can be solved in two ways:  mathematically and graphically.

<u>Graphing</u>

Plot both lines and find where they intersect.  See the attachment.

The intersection points are (1.13, 7.74) and (-4.13, 18.26)

<u>Mathematical</u>

y + 2x = 10

y = 10 - 2x

y = 3x² + 7x - 4

10 - 2x = 3x² + 7x - 4

3x² + 9x - 14 = 0

Solve this using the quadratic equation:

x = 1.13 and -4.13

Use these two values of x to find y:

y = 10 - 2x

y = 10 - 2(1.13)

y = 7.74

y = 10 -2x

y = 10 -2(-4.13)

y =  18.26

The two points are:

(1.13, 7.74) and (-4.13, 18.26)

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