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3 years ago

Are 3 and 8 prime to each other

Mathematics

1 answer:

MAVERICK [17]3 years ago

3 0

Remark

Yes even though 8 is not a prime number. There is nothing that will divide into 3 or 8 the will give a whole number answer when the division is complete.

That means that 3 and 8 are prime to each other in base 10.

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Find the slope (-10,3) (5,10)

barxatty [35]

Answer:

idk

Step-by-step explanation:

i don't know man how can I answer

8 0

3 years ago

Paige rolls a number cube sixty-four times. The number 4 comes up fourteen times. The number 3 comes up six times. Rounded to th

3241004551 [841]

Answer:

31%

Step-by-step explanation:

To determine the probability of obtaining 3 or any number in a roll, we divide the number of outcomes with the sample space.

probability of 3 : n = 6/64 = 3/32 = 0.09375

probability of 4 : n = 14/64 = 7/32 = 0.21875

Since, we use the conjuction "or", we therefore add up these probabilities.

n = 5/16 or 0.3125

Hope this Helps

6 0

3 years ago

Write an equation in slope-intercept form for points through (2, -7), parallel to 7x - 4y = 18

pav-90 [236]

Y=18-7x/-4
gradient = 7/4
parallel lines, same gradient.
y--7=7/4(x-2)
y=7x-14-28/4
y= (7x + 14)/4

6 0

3 years ago

Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

Hope it helps...

3 0

3 years ago

Which visualization tool is more helpful for detecting outliers in data? Select one: a. scatter plot b. histogram c. Boxplot

Tpy6a [65]

Answer:

(A) Scatterplot

Step-by-step explanation:

The most helpful visualization to spot outliers would be a scatterplot.

When collecting data on a scatterplot, you can see how the results are similar and which areas have the most answers and such.

There can be multiply outliers on a scatterplot, and they stand out because while most answers will be clumped together, the outliers will not.

7 0

3 years ago