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2 years ago

What is the distance between points (0,0) and (-3,-4)?

Mathematics

1 answer:

allsm [11]2 years ago

8 0

Answer:

I think its -3, -4

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gtnhenbr [62]

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3 years ago

How can the quotient for problem 2 help you find the quotient for problem 3 ? Problem 2:5 divided by 20 =4 & problem 3: 4 di

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3 years ago

B is the midpoint of AC, E is the midpoint of BD. If A(-9,-4), C(-1,6), and E(-4,-3), find the coordinates of D

Vadim26 [7]

Answer:

(-3, -7)

Step-by-step explanation:

Let $(x_{A,}y_{A}),(x_{B},y_{B}),(x_{C,}y_{C}),(x_{D,}y_{D})(x_{E,}y_{E)} \text{be the coordinates of points A, B, C respectively}\\\\$

The midpoint coordinates $(x_{M},y_{M})$ of any two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are given by $x_{M}=\frac{(x_{1}+x_{2)}}{2}$ and $y_{M}=\frac{y_{1}+y_{2}}{2}$

Since B is the midpoint of AC

$x_{B}=\frac{(x_{A}+x_{C})}{2}=\frac{(-9+(-1)}{2}=\frac{-9-1}{2}=\frac{-10}{2}=-5$

$y_{B}=\frac{(y_{A}+y_{C})}{2}=\frac{(-4+6)}{2}=\frac{2}{2}=1$

Since E is the midpoint of B and D and we are given the coordinates of E as (-4,-3). it follows that

$x_{E}=\frac{x_{B}+x_{D}}{2} = \frac{-4+x_{D}}{2}$

Therefore

$x_{D}=2x_{E}+4=2(-5)+4=-3$

Similarly

$y_{E}=\frac{y_{B}+y_{D}}{2} = \frac{1+x_{D}}{2}y_{D}=2y_{E}-1=2(-3)-7=-7$

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1 year ago

Please help! will give brainliest!!

Ann [662]

Answer:

Step-by-step explanation:

tHE ANSWER IS C

5 0

3 years ago

A bicycle that usually sells for $230 is on sale for 15% off. Find the sale price.

nikitadnepr [17]

$\frac{15}{100} = \frac{x}{230 } \\ x = \frac{15 \times 230}{100} = \frac{3450}{100 } = 34.5$
15% of $230 is $34.5
$230 - 34.5 = 195.5$
so the price is $195.5
hope this helps

6 0

3 years ago