All categories

2 years ago

What is the distance between points (0,0) and (-3,-4)?

Mathematics

1 answer:

allsm [11]2 years ago

8 0

Answer:

I think its -3, -4

You might be interested in

Which of the following is an irrational number?

Sladkaya [172]

Answer:

1.333...

Step-by-step explanation:

because irrational numbers can be repeating decimals, numbers that aren't perfect squares,and numbers that can not be in fraction form.

4 0

3 years ago

Six more than nine times a Number is 456

Nuetrik [128]

Let the number = x
It would be: 9x + 6 = 456
9x = 456 - 6
9x = 450
x = 450 / 9
x = 50

In short, Your Answer would be 50

Hope this helps!

8 0

3 years ago

What is the value of x ?????

Rasek [7]

what............there’s no pic

3 0

3 years ago

Read 2 more answers

7. You are saving $12 per week to purchase a new kayak. Prices start at $300 and

Dovator [93]

Answer:

5>67=87

Step-by-step explanation:

pls mark brainlyest

7 0

3 years ago

Read 2 more answers

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

3 years ago