1+1+1+1=4
2+2+2+2=16
3+3+3+3=?
I won against: Marilyn Wright-Brown
Answer:
(arranged from top to bottom)
System #3, where x=6
System #1, where x=4
System #7, where x=3
System #5, where x=2
System #2, where x=1
Step-by-step explanation:
System #1: x=4

To solve, start by isolating your first equation for y.

Now, plug this value of y into your second equation.

System #2: x=1

Isolate your second equation for y.

Plug this value of y into your first equation.

System #3: x=6

Isolate your first equation for y.

Plug this value of y into your second equation.

System #4: all real numbers (not included in your diagram)

Plug your value of y into your second equation.

<em>all real numbers are solutions</em>
System #5: x=2

Isolate your second equation for y.

Plug in your value of y to your first equation.

System #6: no solution (not included in your diagram)

Isolate your first equation for y.

Plug your value of y into your second equation.

<em>no solution</em>
System #7: x=3

Plug your value of y into your second equation.

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Answer:
center = (-2, 6)
radius = 6
Step-by-step explanation:
<u>Equation of a circle</u>

(where (a, b) is the center and r is the radius)
Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.
Given equation:

Collect like terms and subtract 4 from both sides:

Complete the square for both variables by adding the square of half of the coefficient of
and
to both sides:


Factor both variables:

Therefore:
- center = (-2, 6)
- radius = √36 = 6