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Alisiya [41]
3 years ago
6

Disculpen alguien sabe de algun buen curso o tutorial para saber calculo?

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0
Puedes ver a https://es.khanacademy.org/math/calculus-home
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What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21
docker41 [41]

The linear equation that is perpendicular to the line x+3y=21 is:

y = 3*x - 6

<h3>How to find the equation of the line?</h3>

A general line in the slope-intercept form is written as:

y = m*x + b

Where m is the slope and b is the y-intercept.

Two linear equations are perpendicular if the product between the two slopes is equal to -1.

Rewriting the given line we can get:

x +3y = 21

3y = 21 - x

y = 21/3 - x/3

y = (-1/3)*x + 21/3

Then the slope is (-1/3), if our line is perpendicular to this one, then:

m*(-1/3) = -1

m = 3

our line is:

y = 3*x + b

To find the value of b, we use the fact that our line passes through (1, - 3)

-3 = 3*1 + b

-3 - 3 = b

-6 = b

The line is y = 3*x - 6

Learn more about linear equations:

brainly.com/question/1884491

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3 0
1 year ago
Mary bought a handbag for 15.00naira. if she sold it for 18.00,what was her percentage gain?​
melomori [17]

Answer:

total profit gained = 20%

Step-by-step explanation:

profit = SP - CP = 18 - 15 = 3 naira

total profit percentage =

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hence her total percentage gain was 20%

8 0
3 years ago
Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution
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Consider the equation:

\sqrt{x+2}+4 = 8

Subtracting '4' from both the sides of the equation, we get as

\sqrt{x+2}+4-4= 8-4

\sqrt{x+2}= 4

Squaring on both the sides of the equation, we get

(\sqrt{x+2})^2 = (4)^2

x+2 = 16

Subtracting '2' from both the sides of the equation, we get

x+2-2=16-2

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

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3 years ago
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