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3 years ago

6

Write the fraction as a percent 9/100

2 answers:

viktelen [127]3 years ago

7 0

The answer is 9% because

1% is 1/100 so it is 1 out of 1 hundred

and 9 out of 1 hundred is in simplified form

Semenov [28]3 years ago

6 0

All you have to do is divide 9 from 100 and you would get 0.09. After, you multiply it by 100 and you would get 9 or 9%.

A better example is if the fraction was like 5/8, you would divide 5 from 8 and get 0.625. When you multiply 0.625 by 100, you would get 62.5%.

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What is the slope of the line represented by the equation y<br> 4 X - 3?<br> 0.-<br> to

Leya [2.2K]

Answer:

The slope is 4/1

Step-by-step explanation:

for every 4 units you go up on the y-axis, you go 1 unit on the x-axis.

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3 years ago

Given the side lengths, determine whether the triangle is acute, obtuse, right, or not a triangle: 8,15,23

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3 years ago

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if the cost price of 10 tables is equal to the selling price of 16 tables , find out the gain or loss percentage

Dovator [93]

Hi,

To solve this problem, Let us take the LCM of 10 and 16 which will come 80.

Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n

According to the question, CP of 10 tables is equal to the SP of 16 tables, then

the SP of 16 tables will also be ₹ n.

So, SP of 80 tables will be ₹ 5n

So, Loss = CP-SP

→ 8n - 5n = ₹ 3n

Loss%= (3n×100)/8n

Loss%= 37.5%.

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4 0

3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago

Which statement is true?

iVinArrow [24]

Answer:

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5 0

2 years ago

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