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3 years ago

Jake ran two laps around a running

Mathematics

1 answer:

stiv31 [10]3 years ago

4 0

Answer:

The total distance he ran and rode is 16.05 miles

Step-by-step explanation:

Here, we want to find the total distance that was ran and biked by Jake

For the running, the track measures 1.2 miles and he ran two laps.

That gives a total of 1.2 * 2 = 2.4 miles

For the biking, the track is 4.55 miles and he went 3 laps.

The total amount of laps went is 4.55 * 3 = 13.65 miles

So the total amount of distance he has biked and ran is 13.65 + 2.4 = 16.05 miles

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Is the following sequence arithmetic?<br> 23, -7, -37, -67, …..

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Answer:

No it's not an Arithmetic Sequence since it doesn't have a constant common ratio

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3 years ago

What is an example of a non-random sample?(math)

Sauron [17]

Is the question multiple choice or do you have to write your own down

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3 years ago

Molly needs to classify the triangle below based on angles. Which class is correct? 60° 50° 70° A. acute triangle О B. isosceles

Art [367]

Answer:

A. Actute triangle

Step-by-step explanation:

Is A because an acute triangle is a triangle where all the angles are the same.

Can not be B. because isosceles triangles have two sides that are the same which doesn't relate to angles.

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3 years ago

The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. There

tankabanditka [31]

Answer:

The lifetime value needed is 11.8225 hours.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. This means that $\mu = 11, \sigma = 1$ .

What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages?

This is the value of THE MEAN SAMPLE X when Z has a pvalue of 0.95. That is between Z = 1.64 and Z = 1.65. So we use $Z = 1.645$

Since we need the mean sample, we need to find the standard deviation of the sample, that is:

$s = \frac{\sigma}{\sqrt{4}} = 0.5$

So:

$Z = \frac{X - \mu}{s}$

$1.645 = \frac{X - 11}{0.5}$

$X - 11 = 0.5*1.645$

$X = 11.8225$

The lifetime value needed is 11.8225 hours.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=Y%3D%5Cfrac%7B-2%7D%7Bx%7D%2B4" id="TexFormula1" title="Y=\frac{-2}{x}+4" alt="Y=\frac{-2}{x}+

Studentka2010 [4]

Part A: Vertical asymptote is $x=0$

Part B: Domain is $\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)$

Part C: Horizontal asymptote is $y=4$

Part D: Range is $\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)$

Explanation:

Part A: We need to determine the vertical asymptote

The vertical asymptote of a function can be determined by equating the denominator equal to zero.

Thus, we have,

$x=0$

Hence, the vertical asymptote is $x=0$

Part B: We need to determine the domain

The domain of the function is the set of all independent x - values for which the function is real and well defined.

Let us take the denominator and equate to zero.

Hence, we have, $x=0$

Therefore, the function is undefined at the point $x=0$

Thus, the domain of the function is $\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)$

Part C: We need to determine the horizontal asymptote

The horizontal asymptote of the function can be determined by dividing the leading coefficient of the numerator by leading coefficient of the denominator.

Thus, we have, $y=4$

Hence, the horizontal asymptote of the function is $y=4$

Part D: We need to determine the range

The range of the function is the set of all dependent y -values of the function.

In other words, the range of the function can be determined by substituting the values for x.

Thus, we have,

$\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)$

Therefore, the range of the function is $\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)$

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3 years ago