Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Answer:
-58
Step-by-step explanation:
input
-8^2(3/4)-10
simplify
-8^1.5-10
then solve
:)
3311.85185.... is the quotient. The fraction is 3311 23/27
8z +3 - 2z < 51
6z + 3 < 51
-3. -3
6z < 48
-- ---
6. 6
z<8