First one single solution second no solution 3rd one single forth one infinity and last 2 are single and infinity
Answer:
Step-by-step explanation:
It 14
There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.
The number of unique arrangements is 8!/(2!*3!) = 3,360
Answer:
b). (0, 4)
if you need an explanation, comment, and I will put one in for you :)
