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Alik [6]
3 years ago
6

(Giving brainliest!!)

Mathematics
2 answers:
finlep [7]3 years ago
7 0

Answer:

the crate weighs 26.31

Step-by-step explanation:

add 32.8 and 39.34 together and then subtract 98.45 from the sum. ^^

Step-by-step explanation:

Vitek1552 [10]3 years ago
5 0

Answer:

the crate weighs 26.31

Step-by-step explanation:

add 32.8 and 39.34 together and then subtract 98.45 from the sum. ^^

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Use the list method to write "the perfect square integers between 1 and 80 inclusive".
AnnZ [28]

Answer:

Step-by-step explanation:

1 Answer

1=12.

4=22.

9=32.

16=42.

25=52.

36=62.

49=72.

64=82 .

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2 years ago
Can someone plss help me with this!!!
Maru [420]
If you divide the wages by the number of hours you always get $56.25 so he gets $56.25 per hour.
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3 years ago
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Calculate gcd(77, 30) by using the Euclidean algorithm. Find also integers u and v such that 49u + 30v = 1. Furthermore, find su
VladimirAG [237]

Answer:

1. gcd(77,30)=1

77=2*30+17\\30=1*17+13\\17=1*13+4\\13=3*4+1\\4=4*1+0

Since 1 is the last non zero remainder appearing in these equations then, 1 is the gcd of 77 and 30.

2. u=-11, v=18

Using the Euclidean Algorithm we have that

49=1*30+19\\30=1*19+11\\19=1*11+8\\11=1*8+3\\8=2*3+2\\3=1*2+1\\2=1*2+0

Now, we express the remainder as linear combinations of 49 and 30.

1&=3-2\\ &=3-(8-2*3)=3-8+2*3\\&=(11-8)-8+2(11-8)=3*11-4*8\\&=3*11-4(19-11)=7*11-4*19\\&=7(30-19)-4*19=7*30-11*19\\&=7*30-11(49-30)=\\&=18*30-11*49

Then 1=(-11)49+18*30

3. x=18

If 30x\equiv 1\text{mod 77} then

30x=k*77+1 for some k\in \mathbb{Z}.

Then, if k=7,

30x=7*77+1=540\\x=\frac{540}{30}=18

6 0
3 years ago
Which statement correctly describes the graph of y = x + 9.5?
Vikki [24]

Answer:

A is the answer

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Help if you do this you will get seven years of good luck if you don't you will get seven years of bad luck: (SAT Prep): Find th
KatRina [158]

Answer:

Slope=\frac{7}{2}=3.5

Step-by-step explanation:

Slope of line: Slope\ of\ line\ passing\ through\ (x_1,y_1)\ and\ (x_2,y_2)\ is\ given\ by\ \frac{y_2-y_1}{x_2-x_1}

Here\ (x_1,y_1)=(\frac{2}{7},5)\\\\(x_2,y_2)=(10,39)\\\\Slope=\frac{39-5}{10-\frac{2}{7}}\\\\Slope=\frac{34}{\frac{68}{7}}\\\\Slope=\frac{34\times 7}{68}\\\\Slope=\frac{7}{2}=3.5

5 0
3 years ago
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