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Ilya [14]
3 years ago
5

Can somebody help me with solve this question

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

f⁻¹(y) = y^(-7/17)

Step-by-step explanation:

f(x) = x^(-17/7)

To find the inverse, switch x and y, and solve for y.

x = y^(-17/7)

x^(-7/17) = y

Therefore, f⁻¹(y) = y^(-7/17).

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5 0
3 years ago
Fine the area of the kite.
Sedbober [7]

Answer:

A. 90 sq. units


Step-by-step explanation:


6 0
3 years ago
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5 5/7 x 5 5/7 for a quiz
Sauron [17]

Answer:

61 36/49

Step-by-step explanation:

I took  a test with that question. my answer was right

7 0
3 years ago
Read 2 more answers
the parallel sides of a trapezium are such that the longer side is 4cm more than the shorter side of the distance between them i
saw5 [17]

Answer:

32cm and 28cm

Step-by-step explanation:

Area of a trapezium=0.5 ( sum of parallel sides ) × height

600=0.5( 4+a+a)×20

where a is the length of the shorter side

600÷0.5=(4+2a)×20

1200=(4+2a)×20

1200÷20=4+2a

60=4+2a

60-4=2a

56=2a

56÷2=a

28=a.

since the longer side is 4 cm more than th shorter side , 28 +4=32

4 0
3 years ago
The perimeter of the isosceles ?ABC with the base BC is equal to 40 cm. Perimeter of the equilateral ?BCD is 45 cm. Find AB and
Juliette [100K]

Answer: AB = 12.5, BC = 15

<u>Step-by-step explanation:</u>

Perimeter of ΔBCD = BC + CD + BD. Since it is an isoceles triangle, then BC = CD = BD. So, Perimeter of ΔBCD = 3BC

3BC = 45

<u>÷3   </u>    <u>÷3 </u>

 BC = 15

Perimeter of ΔABC = AB + BC + AC.  Since it is an isosceles triangle with BC as the base, then AB = AC. So, Perimeter of ΔABC = 2AB + BC

2AB + BC = 40

2AB + 15 = 40

<u>          -15</u>  <u> -15 </u>

2AB       = 25

<u>÷2         </u>   <u>÷2  </u>

      AB  = 12.5

7 0
3 years ago
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