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3 years ago

Can somebody help me with solve this question

Mathematics

1 answer:

nexus9112 [7]3 years ago

7 0

Answer:

f⁻¹(y) = y^(-7/17)

Step-by-step explanation:

f(x) = x^(-17/7)

To find the inverse, switch x and y, and solve for y.

x = y^(-17/7)

x^(-7/17) = y

Therefore, f⁻¹(y) = y^(-7/17).

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Choose the definition for the function

uysha [10]

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The answer is C.

Step-by-step explanation:

The first line's slope is 2x and it y-intercept is 4. The second line's slope is simple 1x or just x (they are both the same).

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3 years ago

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3 years ago

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3 years ago

Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su

777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

$a, ar, ar^2,...\\a = 7\\r = 7$

$7, 7^2, 7^3, 7^4...$

Sum of n terms in a geometric progression:

$S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}$

For sum of five terms, we put n= 5, a = 7, r = 7

$S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607$

The sum of first five term of GP is 19607.

Verification:

$2801\times 7 = 19607$

Thus, the sum is equal to product of 2801 and 7.

7 0

3 years ago

PLEASE help. The problem is to find the indicated sum.

alukav5142 [94]

The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].

Hope this helps.

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3 years ago