Answer:
Since the computed value of t= 0.833 does not fall in the critical region we therefore do not reject H0 and may conclude that population mean is greater than 160. Or the sample comes from population with mean of 165.
Step-by-step explanation:
- State the null and alternative hypothesis as
H0: μ= 160 against the claim Ha :μ ≠160
Sample mean = x`= 165
Sample standard deviation= Sd= 12
2. The test statistic to use is
t= x`-μ/sd/√n
which if H0 is true , has t distribution with n-1 = 36-1= 35 degrees of freedom
3. The critical region is t< t (0.025(35)= 2.0306
t= x`-μ/sd/√n
4. t = (165-160)/[12/√(36)] = 5/[6] = 0.833
5. Since the computed value of t= 0.833 does not fall in the critical region we therefore do not reject H0 and may conclude that population mean is greater than 160. Or the sample comes from population with mean of 165.
Now
6. The p-value is 0 .410326 for t= 0.8333 with 35 degrees of freedom.
That is equivalent to 8√10
Answer:
- The length = x = 15 units
- The width = x-5 = 10 units
Step-by-step explanation:
Let 'x' be the length of a rectangle
As the width of a rectangle is 5 units less than the length.
so
width of rectangle will be = w = x - 5 units
Area = 150 square units
Using the formula
Area = length × width
Subtract 50 from both sides
if
As length can not be negative. so
x = 15 units
Hence,
The length = x = 15 units
The width = x-5 = 15-5 = 10 units
Answer:
See explanation for end behavior below
Domain = All Real numbers
Range = All Real numbers
Step-by-step explanation:
This is a typical power function of order 3, and since its coefficient is a negative one (-2), its end behavior is:
As x becomes more and more negative (moving towards the left of the horizontal axis, the values for y will become larger and larger (reaching very positive numbers on the y scale). As x becomes larger and larger (moving towards large values on the positive side of the horizontal axis, the related y values will become more and more negative.
The Domain of the function (the x-values for which the function is defined) consists of all Real numbers.
The same is true for the Range, since the y-values spread over all the real number line.
If the <em>n</em>-th term of the sequence is given by <em>n</em> ² - 2, then the 5th term is obtained by simply replacing <em>n</em> with 5 :
5² - 2 = 25 - 2 = 23
